\(a,A=\left(\cos^220^0+\cos^270^0\right)+\left(\cos^240^0+\cos^250^0\right)\\ A=\left(\cos^220^0+\sin^220^0\right)+\left(\cos^240^0+\sin^240^0\right)=1+1=2\\ b,B=\left(\cos^2\alpha\right)^3+\left(\sin^2\alpha\right)^3+3\sin^2\alpha\cdot\cos^2\alpha\cdot\left(\sin^2\alpha+\cos^2\alpha\right)\\ B=\left(\sin^2\alpha+\cos^2\alpha\right)^3=1^3=1\)

a) 90 – ( 30 – 20) = 90 – 10

                   = 80

90 – 30 – 20 = 60 - 20

                  = 40

b) 100 – (60 + 10) = 100 – 70

                   = 30

100 - 60 + 10 = 40 + 10

                   = 50

c) 135 – (30 + 5) = 135 – 35

                   = 100

135 – 30 – 5 = 105 – 5

                   = 100

d) 70 + (40 – 10) = 70 + 30

                   = 100

70 + 40 – 10 = 110 -10

                   = 100

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a: \(=2\sqrt{5}-2\sqrt{5}+9\sqrt{5}-30\sqrt{5}=-21\sqrt{5}\)

b: \(=2\sqrt{7}-6\sqrt{7}-\dfrac{3}{4}\sqrt{7}-8\sqrt{7}=-\dfrac{51}{4}\sqrt{7}\)

a) 

5 406 x 2 x 4

= 10 812 x 4 

= 43 248

b) 

370 + 9 826 + 6 530

= 10 196 + 6 530

= 16 726

a/ 35 – 2.1¹¹¹ + 3. 7²
= 35 - 2.1 + 3.49
= 35 - 2 + 147
= 33 + 147
= 180
 b/ 5.4³ + 2.3 – 81. 2 + 7
= 5.64 + 6 - 162 + 7
= 320 + 6 - 162 + 7
= 326 - 162 + 7
= 164 + 7
= 171 
c/ 2⁵ + 2.{12 + 2.[3.(5-2)+1]+1}+1 
= 32 + 2.{12 + 2.[3.3+1]+1}+1
= 32 + 2.{12 + 2.10+1}+1
= 32 + 2.{12 + 20 + 1}+1
= 32 + 2.{32+1}+1
= 32 + 2.33 + 1
= 32 + 66 + 1
= 98 + 1
= 99
 d/ 17.131 + 69.17
= 17 . (131+69)
= 17 . 200
= 3400
 e/ 50 – [30 - (6 - 2)² ]
= 50 - [30 - 4²]
= 50 - 14
= 36
 f/ 199 +36 + 201 + 184 + 37 
= (199+201)+(36+184)+37
= 400 + 220 + 37
= 657

a) Thay \(a =  - 4,b = 18\)vào đa thức ta có:

\(A =  - 5a - b - 20 =  - 5. - 4 - 18 - 20 =  - 18\).

b) Thay \(x =  - 1,y = 3,z =  - 2\)vào đa thức ta có:

\(B =  - 8xyz + 2xy + 16y =  - 8. - 1.3. - 2 + 2. - 1.3 + 16.3 =  - 48 - 6 + 48 =  - 6\).

c) Thay \(x =  - 2,y =  - 3\)vào đa thức ta có:

\(C =  - {x^{2021}}{y^2} + 9{x^{2021}} =  - {( - 1)^{2021}}.{( - 3)^2} + 9.{( - 1)^{2021}} =  - ( - 1).9 + 9.( - 1) = 9 + ( - 9) = 0\). 

a: \(=\left(2\sqrt{3}-12\sqrt{3}+15\sqrt{3}\right)\cdot\sqrt{3}=5\sqrt{3}\cdot\sqrt{3}=15\)

b: \(=\left(6\sqrt{2}-16\sqrt{2}+15\sqrt{2}\right):5=\sqrt{2}\)

c: \(=\dfrac{\left(2\sqrt{5}-6\sqrt{5}+15\sqrt{5}\right)}{\sqrt{5}}=17-6=11\)

a) 4 500 : 90 : 25 = 50 : 25 = 2

b) 840 : (3 x 4) = 840 : 12 = 70

c) 682 + 96 : 12 = 682 + 8 = 690

d) 2 784 : 24 – 16 = 116 – 16 = 100